0=32x^2+96x+72

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Solution for 0=32x^2+96x+72 equation: 



0=32x^2+96x+72

We move all terms to the left:

0-(32x^2+96x+72)=0

We add all the numbers together, and all the variables

-(32x^2+96x+72)=0

We get rid of parentheses

-32x^2-96x-72=0

a = -32; b = -96; c = -72;
Δ = b2-4ac
Δ = -962-4·(-32)·(-72)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{96}{-64}=-1+1/2$

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